An ideal transformer consists of a 500-turn primary coil and a 2000-turn secondary coil.If the current in the secondary is 3.0 A,what is the current in the primary?
A) 0.75 A
B) 1.3 A
C) 12 A
D) 24 A
E) 48 A

Question

Quizplus · Accepted Answer

The current in the primary coil can be found using the transformer equation $I_1 = \frac{N_2}{N_1}I_2$, where $I_1$ is the current in the primary coil, $N_1$ and $N_2$ are the number of turns in the primary and secondary coils respectively, and $I_2$ is the current in the secondary coil. Substituting the given values, $I_1 = \frac{2000}{500} \times 3.0 = 4 \times 3.0 = 12$ A.

An Ideal Transformer Consists of a 500-Turn Primary Coil and a 2000-Turn