If a beam of electromagnetic radiation has an intensity of 120 W/m², what is the maximum value of the electric field? (c = 3.0 x 10⁸ m/s, μ₀ = 4π × 10^-7T ∙ m/A, ε₀ = 8.85 × 10^-12 C²/N ∙ m²) A) 1.5 kV/m B) 1.0 µT C) 1.0 µV/m D) 0.30 kV/m E) 0.0032 V/m

Question

Quizplus · Accepted Answer

The maximum value of the electric field can be calculated using the formula:

E = sqrt(I/(c * ε))

where I is the intensity of the radiation, c is the speed of light, and ε is the permittivity of free space.

Substituting the given values, we get:

E = sqrt(120/(3.0E8 * 8.85E-12))

E ≈ 0.30 kV/m

Therefore, the correct choice is D, 0.30 kV/m.

If a Beam of Electromagnetic Radiation Has an Intensity of 120