An optical fiber made of glass with an index of refraction 1.50 is coated with a plastic with index of refraction 1.30.What is the critical angle of this fiber at the glass-plastic interface?
A) 90.0°
B) 41.8°
C) 60.1°
D) 50.2°
E) 61.1°

Question

Quizplus · Accepted Answer

The critical angle can be calculated using Snell's Law: n1 * sin(θc) = n2 * sin(90°), where n1 is the index of refraction of glass (1.50) and n2 is the index of refraction of plastic (1.30). Solving for θc gives sin(θc) = 1.30/1.50, which results in θc ≈ 60.1°.

An Optical Fiber Made of Glass with an Index of Refraction