Upon being struck by 240-nm photons, a metal ejects electrons with a maximum kinetic energy of 1.45 eV. What is the work function of this metal? (h = 6.626 × 10^-34 J ∙ s, c = 3.00 × 10⁸ m/s, 1 eV = 1.60 × 10^-19 J) A) 3.73 eV B) 3.13 eV C) 4.33 eV D) 4.92 eV

Question

Quizplus · Accepted Answer

The work function is given by the equation:$$KE_{max} = hν - Φ$$where:* $$KE_{max}$$ is the maximum kinetic energy of the ejected electrons* h is Planck's constant* ν is the frequency of the incident photons* Φ is the work functionWe can rearrange this equation to solve for the work function:$$Φ = hν - KE_{max}$$Plugging in the given values, we get:$$Φ = (6.626 × 10^{-34} J \cdot s)(3.00 × 10^8 m/s)/(240 × 10^{-9} m) - (1.45 eV)(1.60 × 10^{-19} J/eV)$$$$Φ = 3.73 eV$$Therefore, the work function of the metal is 3.73 eV.

Upon Being Struck by 240-Nm Photons, a Metal Ejects Electrons