A hydrogen atom is in its n = 2 excited state when its electron absorbs a photon of energy 8.5 eV. What is the energy of the resulting free electron? The lowest level energy state of hydrogen is -13.6 eV. (h = 6.626 × 10^-34 J ∙ s, 1 eV = 1.60 × 10^-19 J) A) 5.1 eV B) 6.6 eV C) 6.9 eV D) 7.6 eV

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Quizplus · Accepted Answer

The energy of the n=2 state is -3.4 eV. Absorbing 8.5 eV raises the electron to 5.1 eV above zero, making it a free electron with 5.1 eV of kinetic energy.

A Hydrogen Atom Is in Its N = 2 Excited