Light of wavelength 105 nm falls on a metal surface for which the work function is 5.00 eV. What is the minimum de Broglie wavelength of the photoelectrons emitted from this metal? (h = 6.626 × 10-34 J ∙ s = 4.14 × 10-15 eV ∙ s, c = 3.00 × 108 m/s, mel = 9.11 × 10-31 kg, 1 eV = 1.60 × 10-19 J)
A) 0.24 nm
B) 0.33 nm
C) 0.47 nm
D) 0.66 nm
E) 0.94 nm
Correct Answer:
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