A diatomic molecule has 18 × 10^-5 eV of rotational energy in the l = 2 quantum state. What is its rotational energy in the l = 0 quantum state?

Name: A diatomic molecule has 18 × 10 -5 eV of rotational energy in the l = 2 quantum state. What is its rotational energy in the l = 0 quantum state?
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Question

Quizplus · Accepted Answer

The rotational energy of a diatomic molecule in the quantum state l is given by E = l(l+1)ħ²/2I. For l = 0, the energy is 0 because the term l(l+1) becomes zero.

A Diatomic Molecule Has 18 × 10-5 EV of Rotational

A Diatomic Molecule Has 18 × 10^-5 EV of Rotational