How much energy is released when 1.40 μg of ³H have decayed to ³He? The mass of ³He is 3.016029 u, the mass of ³H is 3.016049 u, and 1 u = 931.494 MeV/c². A) 830 J B) 11,900 J C) 7970 J D) 71,700 J E) 23,900 J

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The energy released in the decay of 1.40 μg of ³H to ³He can be calculated using the mass defect and Einstein's equation E=mc². The mass defect is the difference in mass between the initial and final states of the reaction. In this case, the mass defect is:Δm = (3.016049 u - 3.016029 u) = 0.000020 uConverting this mass defect to energy using Einstein's equation:E = (0.000020 u)(931.494 MeV/c²) = 18.63 MeVSince 1 MeV = 1.602 × 10^-13 J, the energy released in the decay of 1.40 μg of ³H to ³He is:E = (18.63 MeV)(1.602 × 10^-13 J/MeV) = 2.98 × 10^-12 JConverting this energy to joules:E = 2.98 × 10^-12 J = 2.98 μJTherefore, the energy released when 1.40 μg of ³H have decayed to ³He is 2.98 μJ, which is closest to choice A) 830 J.

How Much Energy Is Released When 1