The diploid number of a roundworm species is 4. Assuming there is no crossover, and random segregation of homologs during meiosis, how many different possible combinations of chromosomes might there be in the offspring?

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Quizplus · Accepted Answer

The number of different possible combinations of chromosomes that might occur in the offspring can be calculated using the formula 2n, where n is the number of homologous pairs of chromosomes. In this case, the diploid number is 4, which means that there are two homologous pairs of chromosomes. Using the formula, we get 2^2 = 4. Therefore, each gamete can have one of four possible combinations of chromosomes (i.e. AB, Ab, aB, ab). When these gametes combine during fertilization, the total number of possible combinations of chromosomes in the offspring is 4 x 4 = 16. Therefore, the best choice is C) 16.

The Diploid Number of a Roundworm Species Is 4