The magnitude of the spin angular momentum for an electron is equal to
A) $\sqrt { 3 } \hbar$
B) $\frac { \sqrt { 3 } } { 2 } \hbar$
C) $\hbar$ /2.
D) $\hbar$ /2
E) $\frac { 3 } { 4 } \hbar$

Question

Quizplus · Accepted Answer

The magnitude of the spin angular momentum for an electron is given by $\sqrt{s(s+1)}\hbar$, where $s = 1/2$. Substituting $s = 1/2$ gives $\sqrt{3/4}\hbar = \frac{\sqrt{3}}{2}\hbar$.

The Magnitude of the Spin Angular Momentum for an Electron 3ℏ\sqrt { 3 } \hbar3​ℏ

The Magnitude of the Spin Angular Momentum for an Electron $\sqrt { 3 } \hbar$