How much energy is in a 63 kHz photon of AM-radiation? A)1.0 *10^-³⁸ J B)6.6 *10^-³⁰ J C)4.2 *10^-²⁹ J D)3.1 * 10^-³⁰ J E)13 *10^-²⁹ J

Question

Quizplus · Accepted Answer

The energy of a photon can be calculated using the formula E = hf, where E is the energy in joules, h is Planck's constant (6.626 x 10^-34 J/s), and f is the frequency in hertz. 
Substituting the given values, we get:
E = (6.626 x 10^-34 J/s) x (63 x 10^3 Hz) 
E = 4.175 x 10^-28 J 
Rounding off to two significant figures, we get:
E = 4.2 x 10^-28 J 
Therefore, the best choice is C.

How Much Energy Is in a 63 KHz Photon of AM-Radiation