The light intensity incident on a metallic surface with a work function of 3 eV produces photoelectrons with a maximum kinetic energy of 2 eV.The frequency of the light is doubled.Determine the maximum kinetic energy (in eV).

Question

Quizplus · Accepted Answer

When the frequency of the light is doubled, the energy of the photons is also doubled. Initially, the photon energy is 5 eV (3 eV work function + 2 eV kinetic energy). Doubling the frequency doubles the photon energy to 10 eV. Subtracting the work function (3 eV) from this gives a maximum kinetic energy of 7 eV.

The Light Intensity Incident on a Metallic Surface with a Work