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The Correct Form of Ampere's Law for Circuits with Gaps Bds=0\oint \mathrm { B } \cdot d \mathbf { s } = 0

Question 14

Multiple Choice

The correct form of Ampere's law for circuits with gaps in them is


A) Bds=0\oint \mathrm { B } \cdot d \mathbf { s } = 0 .
B) Bds=Ienciosed \oint \mathbf { B } \cdot d \mathbf { s } = I _ { \text {enciosed } } .
C) Bds=μ0Ienclosed \oint \mathbf { B } \cdot d \mathbf { s } = \mu _ { 0 } I _ { \text {enclosed } } .
D) Bds=μ0Ienclosed +μ0ε0dΦEdt\oint \mathbf { B } \cdot d \mathbf { s } = \mu _ { 0 } I _ { \text {enclosed } } + \mu _ { 0 } \varepsilon _ { 0 } \frac { d \Phi _ { E } } { d t } .
E) Bds=μ0Ienclosed +μ0ε0dΦIdtε0(μ0) 2dΦBdt\oint \mathbf { B } \cdot d \mathbf { s } = \mu _ { 0 } I _ { \text {enclosed } } + \mu _ { 0 } \varepsilon _ { 0 } \frac { d \Phi _ { I } } { d t } - \frac { \varepsilon _ { 0 } } { \left( \mu _ { 0 } \right) ^ { 2 } } \frac { d \Phi _ { B } } { d t } .

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