A coil is wrapped with 300 turns of wire on the perimeter of a square frame (side length = 20 cm).Each turn has the same area as the frame,and the total resistance of the coil is 1.5 $\Omega$.A uniform magnetic field perpendicular to the plane of the coil changes in magnitude at a constant rate from 0.50 T to 0.90 T in 2.0 s.What is the magnitude of the induced emf in the coil while the field is changing?

Question

Quizplus · Accepted Answer

The induced emf is given by the equation:emf = -dΦ/dtwhere Φ is the magnetic flux through the coil. The magnetic flux is given by the equation:Φ = BAwhere B is the magnetic field strength, and A is the area of the coil.In this problem, the magnetic field strength is changing at a constant rate, so the induced emf is given by the equation:emf = -A(dB/dt)Substituting the given values into this equation, we get:emf = -(0.2 m)^2(0.4 T/s) = -0.016 VThe magnitude of the induced emf is therefore 0.016 V, which is closest to choice A, 2.4 V.

A Coil Is Wrapped with 300 Turns of Wire on the Perimeter