A 20-cm length of wire is held along an east-west direction and moved horizontally to the north with a speed of 3.0 m/s in a region where the magnetic field of the earth is 60 $\mu$T directed 30$\degree$ below the horizontal.What is the magnitude of the potential difference between the ends of the wire?
A)36 $\mu$V
B)18 $\mu$V
C)31 $\mu$V
D)24 $\mu$V
E)21 $\mu$V

Question

Quizplus · Accepted Answer

The potential difference (emf) induced in the wire is given by the formula emf = B * v * L * sin(θ), where B is the magnetic field strength, v is the velocity, L is the length of the wire, and θ is the angle between the magnetic field and the direction of motion. Substituting the given values: B = 60 μT, v = 3.0 m/s, L = 0.20 m, and θ = 30°, we get emf = 60 * 10^-6 T * 3.0 m/s * 0.20 m * sin(30°) = 18 μV.

A 20-Cm Length of Wire Is Held Along an East-West μ\muμ

A 20-Cm Length of Wire Is Held Along an East-West $\mu$