A conducting bar of length L rotates with a constant angular speed of +2.0 rad/s about a pivot P at one end,as shown.A uniform magnetic field (magnitude = 0.20 T)is directed into the paper.If L = 0.40 m,what is the potential difference,V_A - V_P? A)-12 mV B)+8.0 mV C)-8.0 mV D)+12 mV E)-16 mV

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The Answer of A conducting bar of length L rotates with a constant angular speed of +2.0 rad/s about a pivot P at one end,as shown.A uniform magnetic field (magnitude = 0.20 T)is directed into the paper.If L = 0.40 m,what is the potential difference,V_A - V_P? A)-12 mV B)+8.0 mV C)-8.0 mV D)+12 mV E)-16 mV

A Conducting Bar of Length L Rotates with a Constant