A segment of wire carries a current of 25 A along the x axis from x = -2.0 m to x = 0 and then along the y axis from y = 0 to y = 3.0 m.In this region of space,the magnetic field is equal to 40 mT in the positive z direction.What is the magnitude of the force on this segment of wire?
A)2.0 N
B)5.0 N
C)1.0 N
D)3.6 N
E)3.0 N

Question

Quizplus · Accepted Answer

To find the force on the wire segment, we can use the formula:

F = I L B sinθ

where I is the current, L is the length of the wire segment, B is the magnetic field, and θ is the angle between the wire segment and the magnetic field (which is 90 degrees in this case).

First, let's find the length of the wire segment. Along the x axis, the wire segment extends from x = 102.0 m to x = 0, so its length is 102.0 m. Along the y axis, the wire segment extends from y = 0 to y = 3.0 m, so its length is 3.0 m. The total length of the wire segment is therefore:

L = 102.0 m + 3.0 m = 105.0 m

Next, we can plug in the values for I, L, B, and θ:

F = (25 A)(105.0 m)(40 mT) sin(90°)
  = (25 A)(105.0 m)(0.04 T)
  = 105 N

Therefore, the magnitude of the force on the wire segment is 105 N, which is closest to answer choice D (3.6 N).

A Segment of Wire Carries a Current of 25 a Along