If a = 2.0 cm,b = 5.0 cm,and I = 20 A,what is the magnitude of the magnetic field at the point P?

Question

Quizplus · Accepted Answer

The magnetic field at a distance r from a long straight wire carrying current I can be calculated using the formula B = (μ0 I)/(2πr), where μ0 is the permeability of free space (equal to 4π × 10^-7 T·m/A). In this case, the wire is perpendicular to the plane of the page, and point P is a distance of (5.0 - 2.0)/2 = 1.5 cm away from the wire. Thus, we have: B = (μ0 I)/(2πr) = (4π × 10^-7 T·m/A)(20 A)/(2π(0.015 m)) ≈ 6.0 μT = 6.0 × 10^-5 T. Therefore, the best answer is D: 6.0 μT (or 6.0 × 10^-5 T).

If a = 20 Cm,b = 5 μ\muμ T B)75 μ\muμ T C)90

If a = 20 Cm,b = 5 $\mu$ T
B)75 $\mu$ T
C)90