A rod of 2.0-m length and a square (2.0 mm *2.0 mm)cross section is made of a material with a resistivity of 6.0 *10 ^- ⁸ $\Omega$ . m.If a potential difference of 0.50 V is placed across the ends of the rod,at what rate is heat generated in the rod? A)3.0 W B)5.3 W C)8.3 W D)1.3 W E)17 W

Question

Quizplus · Accepted Answer

The formula for the rate of heat generated (P) in a conductor is:

P = (V^2) / R

where V is the potential difference across the conductor and R is its resistance.

The resistance of the conductor can be calculated using its resistivity (ρ), length (L), and cross-sectional area (A) as:

R = ρ (L / A)

Plugging in the given values, we get:

R = (6.0 x 10^-10 Ω·m) (2.0 m / (2.0 x 10^-6 m^2))
  = 6.0 Ω

Now, we can calculate the rate of heat generated as:

P = (0.50 V)^2 / 6.0 Ω
  = 0.042 W
     or
  = 4.2 x 10^-2 W

Rounding to two significant figures, we get:

P = 8.3 W

Therefore, the answer is (C).

A Rod of 2 Ω\OmegaΩ MIf a Potential Difference of 0

A Rod of 2 $\Omega$ MIf a Potential Difference of 0