A cook plugs a 500 W crockpot and a 1 000 W kettle into a 240 V power supply, all operating on direct current. When we compare the two, we find that A) I_crockpot R_kettle.

Question

A cook plugs a 500 W crockpot and a 1 000 W kettle into a 240 V power supply, all operating on direct current. When we compare the two, we find that A) I_crockpot < I_kettle and R_crockpot < R_kettle. B) I_crockpot < I_kettle and R_crockpot > R_kettle. C) I_crockpot = I_kettle and R_crockpot = R_kettle. D) I_crockpot > I_kettle and R_crockpot < R_kettle. E) I_crockpot > I_kettle and R_crockpot > R_kettle.

Quizplus · Accepted Answer

The current (I) drawn by an appliance can be calculated using the formula $I = \frac{P}{V}$, where $P$ is the power in watts and $V$ is the voltage. For the crockpot, $I = \frac{500}{240}$ and for the kettle, $I = \frac{1000}{240}$. This shows that the kettle draws more current than the crockpot. The resistance (R) of an appliance can be calculated using the formula $R = \frac{V^2}{P}$. Therefore, the crockpot, with lower power, has higher resistance compared to the kettle with higher power.

A Cook Plugs a 500 W Crockpot and a 1