How long will it take a charged 80-$\mu$F capacitor to lose 20% of its initial energy when it is allowed to discharge through a 45- $\Omega$ resistor?
A)0.92 ms
B)0.64 ms
C)0.40 ms
D)0.19 ms
E)0.80 ms

Question

Quizplus · Accepted Answer

The time constant (τ) of the circuit is given as:

τ = RC = 45 x 80 x 10^-6 = 3.6 ms

To find the time taken to lose 20% of initial energy, we can use the following formula:

t = τ x ln(1/0.8) = 0.4 ms

Therefore, the best choice is C) 0.40 ms.

How Long Will It Take a Charged 80- μ\muμ F Capacitor to Lose 20% of Its Initial Energy When

How Long Will It Take a Charged 80- $\mu$ F Capacitor to Lose 20% of Its Initial Energy When