A charged particle (q = -8.0 mC),which moves in a region where the only force acting on the particle is an electric force,is released from rest at point A.At point B the kinetic energy of the particle is equal to 4.8 J.What is the electric potential difference V_B- V_A? A)-0.60 kV B)+0.60 kV C)+0.80 kV D)-0.80 kV E)+0.48 kV

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The Answer of A charged particle (q = -8.0 mC),which moves in a region where the only force acting on the particle is an electric force,is released from rest at point A.At point B the kinetic energy of the particle is equal to 4.8 J.What is the electric potential difference V_B- V_A? A)-0.60 kV B)+0.60 kV C)+0.80 kV D)-0.80 kV E)+0.48 kV

A Charged Particle (Q = -8