The electric field in a region of space is given by E_x = (3.0x)N/C,E_y = E_z = 0,where x is in m.Points A and B are on the x axis at x_A = 3.0 m and x_B = 5.0 m.Determine the potential difference V_B - V_A. A)-24 V B)+24 V C)-18 V D)+30 V E)-6.0 V

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The potential difference is given by:$$V_B - V_A = -\int_A^B E_x dx$$$$= -\int_3^5 (3.0x)dx$$$$= -3.0 \left[\frac{x^2}{2}\right]_3^5$$$$= -3.0 \left(\frac{25}{2} - \frac{9}{2}\right)$$$$= -3.0 (8)$$$$= -24 V$$Therefore, the potential difference is -24 V.

The Electric Field in a Region of Space Is Given