A 0.16 pF parallel-plate capacitor is charged to 10 V.Then the battery is disconnected from the capacitor.When 1.00 * 10⁷ positive charges of magnitude |e| are now placed on the positive plate of the capacitor,the voltage between the plates changes by A)-5.0 V. B)-1.1 V. C)0 V. D)+1.1 V. E)+5.0 V.

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The Answer of A 0.16 pF parallel-plate capacitor is charged to 10 V.Then the battery is disconnected from the capacitor.When 1.00 * 10⁷ positive charges of magnitude |e| are now placed on the positive plate of the capacitor,the voltage between the plates changes by A)-5.0 V. B)-1.1 V. C)0 V. D)+1.1 V. E)+5.0 V.

A 016 PF Parallel-Plate Capacitor Is Charged to 10 V