When a capacitor has a charge of magnitude 80 $\mu$C on each plate the potential difference across the plates is 16 V.How much energy is stored in this capacitor when the potential difference across its plates is 42 V?
A)1.0 mJ
B)4.4 mJ
C)3.2 mJ
D)1.4 mJ
E)1.7 mJ

Question

Quizplus · Accepted Answer

The energy stored in a capacitor is given by the formula E = 1/2 CV^2, where C is the capacitance and V is the potential difference across the plates. In this case, the capacitance is 80 μF and the potential difference is 42 V. Plugging these values into the formula, we get E = 1/2 * 80 μF * (42 V)^2 = 4.4 mJ.

When a Capacitor Has a Charge of Magnitude 80 μ\muμ C on Each Plate the Potential Difference Across the Plates

When a Capacitor Has a Charge of Magnitude 80 $\mu$ C on Each Plate the Potential Difference Across the Plates