Into the gap between the plates of a parallel plate capacitor of capacitance $C _ { 0 }$ a slab of metal is inserted halfway between the plates filling one fourth of the gap between the plates.What is the resulting new capacitance?
A) $\frac { 3 } { 4 } C _ { 0 }$
B) $\frac { 4 } { 3 } C _ { 0 }$
C) $\frac { 9 } { 16 } C _ { 0 }$
D) $\frac { 16 } { 9 } C _ { 0 }$
E) $\frac { 5 } { 4 } C _ { 0 }$

Question

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The Answer of Into the gap between the plates of a parallel plate capacitor of capacitance $C _ { 0 }$ a slab of metal is inserted halfway between the plates filling one fourth of the gap between the plates.What is the resulting new capacitance?
A) $\frac { 3 } { 4 } C _ { 0 }$
B) $\frac { 4 } { 3 } C _ { 0 }$
C) $\frac { 9 } { 16 } C _ { 0 }$
D) $\frac { 16 } { 9 } C _ { 0 }$
E) $\frac { 5 } { 4 } C _ { 0 }$

Into the Gap Between the Plates of a Parallel Plate C0C _ { 0 }C0​

Into the Gap Between the Plates of a Parallel Plate $C _ { 0 }$