If we define the gravitational field $\overrightarrow { \mathbf { g } } = \frac { - G M _ { \text {source } } } { r ^ { 2 } } \hat { \mathbf { r } }$ ,where $\hat{r}$ is a unit radial vector,then Gauss's Law for gravity is
A) $\oint \overrightarrow { \mathbf { g } } \cdot d \mathbf { A } = - G M _ { \text {source } }$ .
B) $\oint \overrightarrow { \mathbf { g } } \cdot d \mathbf { A } = + G M _ { \text {source } }$ .
C) $\oint \overrightarrow { \mathbf { g } } \cdot d \mathbf { A } = - 4 \pi G M _ { \text {source } }$ .
D) $\oint \overrightarrow { \mathbf { g } } \cdot d \mathbf { A } = + 4 \pi G M _ { \text {source } }$ .
E) $\oint \overrightarrow { \mathbf { g } } \cdot d \mathbf { A } = - 4 \pi G M _ { \text {source } } m _ { \text {object } }$ .

Question

Quizplus · Accepted Answer

Gauss's Law for gravity states that the flux of the gravitational field through a closed surface is proportional to the enclosed mass, with a factor of $-4\pi G$.

If We Define the Gravitational Field g→=−GMsource r2r^\overrightarrow { \mathbf { g } } = \frac { - G M _ { \text {source } } } { r ^ { 2 } } \hat { \mathbf { r } }g​=r2−GMsource ​​r^

If We Define the Gravitational Field $\overrightarrow { \mathbf { g } } = \frac { - G M _ { \text {source } } } { r ^ { 2 } } \hat { \mathbf { r } }$