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Whitney Says That Gauss's Law Can Be Used to Find EdA=0\overrightarrow { \mathbf { E } } \cdot d \overrightarrow { \mathbf { A } } = 0

Question 114

Multiple Choice

Whitney says that Gauss's Law can be used to find the electric field of a sufficiently symmetrical distribution of charge as long as EdA=0\overrightarrow { \mathbf { E } } \cdot d \overrightarrow { \mathbf { A } } = 0 over the whole Gaussian surface.Algie says that the electric field must be a constant vector over the entire Gaussian surface.Which one,if either,is correct?


A) Whitney,because that means no charge is enclosed within the Gaussian surface.
B) Algie,because a constant electric field means that EdA=0\oint \overrightarrow { \mathbf { E } } \cdot d \overrightarrow { \mathbf { A } } = 0 .
C) Both,because the conditions in (a) and (b) are equivalent.
D) Neither,because the electric field can be found from Gauss's law only if EdA=0\overrightarrow { \mathbf { E } } \cdot d \overrightarrow { \mathbf { A } } = 0 holds only over a portion of the Gaussian surface.
E) Neither,because the charge distribution must be symmetric if EdA=0\overrightarrow { \mathbf { E } } \cdot d \overrightarrow { \mathbf { A } } = 0 anywhere on the surface.

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