A long nonconducting cylinder (radius = 6.0 mm)has a nonuniform volume charge density given by $\alpha$r²,where $\alpha$ = 6.2 mC/m⁵ and r is the distance from the axis of the cylinder.What is the magnitude of the electric field at a point 2.0 mm from the axis?

Question

Quizplus · Accepted Answer

The electric field inside a nonconducting cylinder with a nonuniform charge density can be found using Gauss's law. The charge density is given as a function of r, so we integrate the charge density over the volume to find the enclosed charge. Then, apply Gauss's law to find the electric field at 2.0 mm from the axis.

A Long Nonconducting Cylinder (Radius = 6 α\alphaα R2,where α\alphaα = 62 MC/m5 and R Is the Distance from the Axis

A Long Nonconducting Cylinder (Radius = 6 $\alpha$ R²,where $\alpha$ = 62 MC/m⁵ and R Is the Distance from the Axis