The nucleus of lead-208, ${ } _ { 82 } ^ { 208 } \mathrm {~Pb}$ ,has 82 protons within a sphere of radius 6.34 *10 ^- ¹⁵.Each electric charge has a value of 1.60 *10 ^- ¹⁹ C.Assuming that the protons create a spherically symmetric distribution of charge,calculate the electric field at the surface of the nucleus.

Question

The nucleus of lead-208,

{ } _ { 82 } ^ { 208 } \mathrm {~Pb}

,has 82 protons within a sphere of radius 6.34 *10 ^- ¹⁵.Each electric charge has a value of 1.60 *10 ^- ¹⁹ C.Assuming that the protons create a spherically symmetric distribution of charge,calculate the electric field at the surface of the nucleus.

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The Answer of The nucleus of lead-208, ${ } _ { 82 } ^ { 208 } \mathrm {~Pb}$ ,has 82 protons within a sphere of radius 6.34 *10 ^- ¹⁵.Each electric charge has a value of 1.60 *10 ^- ¹⁹ C.Assuming that the protons create a spherically symmetric distribution of charge,calculate the electric field at the surface of the nucleus.

The Nucleus of Lead-208 82208 Pb{ } _ { 82 } ^ { 208 } \mathrm {~Pb}82208​ Pb

The Nucleus of Lead-208 ${ } _ { 82 } ^ { 208 } \mathrm {~Pb}$