A 5-kg piece of lead (specific heat 0.03 cal/g.$\degree$C)having a temperature of 80$\degree$C is added to 500 g of water having a temperature of 20$\degree$C.What is the final equilibrium temperature (in $\degree$C)of the system?

Question

Quizplus · Accepted Answer

The final equilibrium temperature can be calculated using the principle of conservation of energy, where the heat lost by the lead equals the heat gained by the water. Solving the equation for equilibrium temperature gives approximately 34°C.

A 5-Kg Piece of Lead (Specific Heat 0 °\degree° C)having a Temperature of 80

A 5-Kg Piece of Lead (Specific Heat 0 $\degree$ C)having a Temperature of 80