Determine the work done by 5 moles of an ideal gas that is kept at 100 $\degree$C in an expansion from 1 liter to 5 liters. A)2.5 * 10⁴ J B)1.1 *10⁴ J C)6.7* 10³ J D)2.9 * 10³ J E)8.4 * 10³ J

Question

Quizplus · Accepted Answer

The work done by an ideal gas in an isothermal expansion is given by the formula W = -nRTln(V2/V1), where n is the number of moles of gas, R is the ideal gas constant, T is the temperature in Kelvin, and V1 and V2 are the initial and final volumes, respectively.In this problem, we have n = 5 moles, R = 0.0821 Latm/(molK), T = 100°C + 273.15 = 373.15 K, V1 = 1 liter, and V2 = 5 liters. Plugging these values into the formula, we get:W = -5 moles * 0.0821 Latm/(molK) * 373.15 K * ln(5 liters / 1 liter)= -2.5 Latm= -2.5 * 101.3 J= -253.25 JTherefore, the work done by the gas is -253.25 J, which is closest to choice A, 2.5 × 104 J.

Determine the Work Done by 5 Moles of an Ideal °\degree°

Determine the Work Done by 5 Moles of an Ideal $\degree$