A child has a temperature of 101$\degree$F.If her total cross-sectional area is 2 m²,find the energy lost each second (in W)due to radiation,assuming the emissivity is 1.(Assume the room temperature is 70$\degree$F. ) A)217 B)180 C)90 D)68 E)850

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The energy lost due to radiation can be calculated using the Stefan-Boltzmann law: P = εσA(T⁴ - T₀⁴), where ε is the emissivity, σ is the Stefan-Boltzmann constant (5.67 x 10⁻⁸ W/m²K⁴), A is the area, T is the temperature of the body in Kelvin, and T₀ is the ambient temperature in Kelvin. Convert the temperatures from Fahrenheit to Kelvin, then substitute the values into the formula to find the power (energy per second) lost.

A Child Has a Temperature of 101 °\degree° FIf Her Total Cross-Sectional Area Is 2 M2,find the Energy

A Child Has a Temperature of 101 $\degree$ FIf Her Total Cross-Sectional Area Is 2 M²,find the Energy