When the coefficient of linear expansion,$\alpha$,and the temperature change,T_f - T_i,are large,a length L_i of a solid substance expands in length to A)L_f = $\alpha$L_i(T_f - T_i). B)L_f = L_i[1 + $\alpha$(T_f - T_i)]. C)L_f = L_i[1 + ln($\alpha$(T_f - T_i))]. D) $L _ { f } = L _ { i } e ^ { \alpha \left( T _ { f } - T _ { 1 } \right) }$ . E) $L _ { f } = L _ { i } \left[ 1 + e ^ { \alpha \left( T _ { f } - T _ { i } \right) } \right]$ .

Question

Quizplus · Accepted Answer

For large temperature changes, the exponential form $L_f = L_i e^{\alpha (T_f - T_i)}$ is used to account for non-linear expansion.

When the Coefficient of Linear Expansion α\alphaα ,And the Temperature Change,Tf - Ti,are Large,a Length Li of Change,Tf

When the Coefficient of Linear Expansion $\alpha$ ,And the Temperature Change,T_f - T_i,are Large,a Length L_i of Change,T_f