An iron block of density $\rho$_Fe and of volume l³ is immersed in a fluid of density $\rho$_fluid.The block hangs from a scale which reads W as the weight.The top of the block is a height h below the surface of the fluid.The correct equation for the reading of the scale is A)W = ($\rho$_Fe-$\rho$_fluid)ghl². B)W = ($\rho$_fluid -$\rho$_Fe)gl³. C)W = ($\rho$_Fe -$\rho$_fluid)gl³. D)W = ($\rho$_Fe + $\rho$_fluid)ghl². E)W = ($\rho$_Fe + $\rho$_fluid)gl³.

Question

Quizplus · Accepted Answer

The correct equation for the reading of the scale is W = (F1F1F1S1F1F1F10_Fe F1F1F1S1F1F1F10 F1F1F1S1F1F1F10_fluid)gl³.This is because the weight of the block is equal to the difference between the buoyant force and the weight of the fluid displaced by the block. The buoyant force is equal to the weight of the fluid displaced by the block, which is equal to the volume of the block times the density of the fluid times the acceleration due to gravity. The weight of the fluid displaced by the block is equal to the volume of the block times the density of the fluid times the acceleration due to gravity.

An Iron Block of Density ρ\rhoρ Fe and of Volume L3 Is Immersed in a Fluid

An Iron Block of Density $\rho$ _Fe and of Volume L³ Is Immersed in a Fluid