For the wave described by $y = 0.15 \sin \left[ \frac { \pi } { 16 } ( 2 x - 64 t ) \right] \text { (SI units) }$ ,determine the x coordinate of the second maximum when t = 0.
A)20 m
B)18 m
C)24 m
D)28 m
E)16 m

Question

Quizplus · Accepted Answer

The second maximum occurs when the argument of the sine function is $\frac{\pi}{2}$. Therefore, we have:$$\frac{\pi}{16}(2x-64t)=\frac{\pi}{2}$$Solving for x, we get:$$x=\frac{64t}{2}+8=32t+8$$At t=0, we have:$$x=32(0)+8=\boxed{8\text{ m}}$$

For the Wave Described By y=0.15sin⁡[π16(2x−64t)] (SI units) y = 0.15 \sin \left[ \frac { \pi } { 16 } ( 2 x - 64 t ) \right] \text { (SI units) }y=0.15sin[16π​(2x−64t)] (SI units)

For the Wave Described By $y = 0.15 \sin \left[ \frac { \pi } { 16 } ( 2 x - 64 t ) \right] \text { (SI units) }$