The oscillation of the 2.0-kg mass on a spring is described by $x = 3.0 \cos ( 4.0 t + 0.80 )$ where x is in centimeters and t is in seconds.What is the force constant of the spring?
A)4.0 N/m
B)0.80 N/m
C)16 N/m
D)32 N/m
E)2.0 $\pi$ N/m

Question

Quizplus · Accepted Answer

The angular frequency $\omega$ is 4.0 rad/s. The force constant $k$ is given by $k = m\omega^2$. Substituting $m = 2.0$ kg and $\omega = 4.0$ rad/s, we get $k = 2.0 \times (4.0)^2 = 32$ N/m.

The Oscillation of the 2 x=3.0cos⁡(4.0t+0.80)x = 3.0 \cos ( 4.0 t + 0.80 )x=3.0cos(4.0t+0.80)

The Oscillation of the 2 $x = 3.0 \cos ( 4.0 t + 0.80 )$