A 2.00 m-long 6.00 kg ladder pivoted at the top hangs down from a platform at the circus.A 42.0 kg trapeze artist climbs to a point where her center of mass is at the center of the ladder and swings at the system's natural frequency.The angular frequency (in s ^- ¹)of the system of ladder and woman is A)1.01. B)3.07. C)4.03. D)8.05. E)16.2.

Question

Quizplus · Accepted Answer

The system's natural frequency can be calculated using the formula for the angular frequency of a physical pendulum: ω = √(g / L_eff), where L_eff is the effective length. Here, the center of mass of the system is at the midpoint of the ladder, so L_eff = 1.00 m. Using g = 9.81 m/s², ω = √(9.81 / 1.00) ≈ 3.13 s⁻¹, which is closest to 3.07 s⁻¹.

A 200 M-Long 6