Knowing that $g = 9.80 \frac { \mathrm { m } } { \mathrm { s } ^ { 2 } }$ at sea level and that R_E = 6.37 * 10⁶ m,we find that the value of g in $\frac { \mathrm { m } } { \mathrm { s } ^ { 2 } }$ at a distance R_E from the surface of the Earth is A)1.23. B)2.45. C)4.90. D)7.35. E)9.80.

Question

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The Answer is B

Knowing That g=9.80ms2g = 9.80 \frac { \mathrm { m } } { \mathrm { s } ^ { 2 } }g=9.80s2m​

Knowing That $g = 9.80 \frac { \mathrm { m } } { \mathrm { s } ^ { 2 } }$