Four identical particles (mass of each = 0.40 kg)are placed at the vertices of a rectangle (2.0 m * 3.0 m)and held in those positions by four light rods which form the sides of the rectangle.What is the moment of inertia of this rigid body about an axis that passes through the mid-points of the longer sides and is parallel to the shorter sides? A)2.7 kg.m² B)3.6 kg.m² C)3.1 kg.m² D)4.1 kg.m² E)1.6 kg.m²

Question

Quizplus · Accepted Answer

The moment of inertia about the given axis is calculated by considering the perpendicular distance of each particle from the axis. The axis is parallel to the shorter side (2.0 m) and passes through the midpoints of the longer sides (3.0 m). Each particle is 1.5 m away from the axis. Using the formula I = Σmr², where m = 0.40 kg and r = 1.5 m, the total moment of inertia is 4 * 0.40 * (1.5)² = 3.6 kg·m².

Four Identical Particles (Mass of Each = 0