A 1.0-kg block is pushed up a rough 22$\degree$inclined plane by a force of 7.0 N acting parallel to the incline.The acceleration of the block is 1.4 m/s² up the incline.Determine the magnitude of the force of friction acting on the block. A)1.9 N B)2.2 N C)1.3 N D)1.6 N E)3.3 N

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Quizplus · Accepted Answer

The force of friction is equal to the difference between the applied force and the force required to accelerate the block up the incline. The force required to accelerate the block is ma, where m is the mass of the block and a is the acceleration of the block. The applied force is 7.0 N. Therefore, the force of friction is 7.0 N - (1.0 kg)(1.4 m/s^2) = 1.9 N.

A 10-Kg Block Is Pushed Up a Rough 22 °\degree° Inclined Plane by a Force of 7

A 10-Kg Block Is Pushed Up a Rough 22 $\degree$ Inclined Plane by a Force of 7