A particle moves in the xy plane with a constant acceleration given by $\overrightarrow { \mathbf { a } } = - 4.0 \hat { \mathbf { j } } \mathrm { m } / \mathrm { s } ^ { 2 }$ .At t = 0,its position and velocity are 10 i? and $( - 2.0 \tilde { \mathbf { i } } + 8.0 \tilde { \mathbf { j } } ) \mathrm { m } / \mathrm { s }$ ,respectively.What is the distance from the origin to the particle at t = 2.0 s?
A)6.4 m
B)10 m
C)8.9 m
D)2.0 m
E)6.2 m

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The Answer of A particle moves in the xy plane with a constant acceleration given by $\overrightarrow { \mathbf { a } } = - 4.0 \hat { \mathbf { j } } \mathrm { m } / \mathrm { s } ^ { 2 }$ .At t = 0,its position and velocity are 10 i? and $( - 2.0 \tilde { \mathbf { i } } + 8.0 \tilde { \mathbf { j } } ) \mathrm { m } / \mathrm { s }$ ,respectively.What is the distance from the origin to the particle at t = 2.0 s?
A)6.4 m
B)10 m
C)8.9 m
D)2.0 m
E)6.2 m

A Particle Moves in the Xy Plane with a Constant a→=−4.0j^m/s2\overrightarrow { \mathbf { a } } = - 4.0 \hat { \mathbf { j } } \mathrm { m } / \mathrm { s } ^ { 2 }a=−4.0j^​m/s2

A Particle Moves in the Xy Plane with a Constant $\overrightarrow { \mathbf { a } } = - 4.0 \hat { \mathbf { j } } \mathrm { m } / \mathrm { s } ^ { 2 }$