An object moving on the x axis with a constant acceleration increases its x coordinate by 80 m in a time of 5.0 s and has a velocity of +20 m/s at the end of this time.Determine the acceleration of the object during this motion. A)-1.6 m/s² B)+6.4 m/s² C)+1.6 m/s² D)-2.0 m/s² E)-6.4 m/s²

Question

Quizplus · Accepted Answer

We can use the following kinematics equation to determine the acceleration of the object: 
Δx = v0t + 0.5at^2

Where Δx is the displacement (80 m), v0 is the initial velocity (0 m/s), t is the time (5.0 s), and a is the acceleration (unknown).

Rearranging the equation, we get: 
a = 2(Δx - v0t) / t^2

Substituting the given values: 
a = 2(80 m - 0 m/s x 5.0 s) / (5.0 s)^2 = 1.6 m/s^2

Therefore, the acceleration of the object during this motion is +1.6 m/s^2, which is choice C.

An Object Moving on the X Axis with a Constant