Consider the S_N2 reaction of butyl bromide with OH^- ion. CH₃CH₂CH₂CH₂Br + OH^- $\rightarrow$ CH₃CH₂CH₂CH₂OH + Br^-
Assuming no other changes,what effect on the rate would result from simultaneously doubling the concentrations of both butyl bromide and OH^- ion?

Question

Consider the S_N2 reaction of butyl bromide with OH^- ion. CH₃CH₂CH₂CH₂Br + OH^-

\rightarrow

CH₃CH₂CH₂CH₂OH + Br^-
Assuming no other changes,what effect on the rate would result from simultaneously doubling the concentrations of both butyl bromide and OH^- ion?

Quizplus · Accepted Answer

In an S_N2 reaction, the rate is dependent on the concentration of both the substrate (butyl bromide) and the nucleophile (OH^-). Doubling both concentrations results in a fourfold increase in the rate (2 x 2 = 4).

Consider the SN2 Reaction of Butyl Bromide with OH- Ion →\rightarrow→

Consider the S_N2 Reaction of Butyl Bromide with OH^- Ion $\rightarrow$