What is the structure of the compound in the following ¹H-NMR spectrum with the molecular formula C₉H₁₄O? IR data shows no characteristic peak around 1700 cm^-1.The ¹³C-NMR chemical shifts (ppm): 108.4,50.9,31.6,23.5,2.0.Relative integration is known.

Question

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The absence of a characteristic peak around 1700 cm-1 in the IR spectrum suggests the absence of a carbonyl group (C=O), which rules out options A, B, D, and E.
The 13C-NMR chemical shifts (ppm) are 108.4, 50.9, 31.6, 23.5, and 2.0, which correspond to a carbon adjacent to a heteroatom, a quaternary carbon, a methylene carbon, a methine carbon, and a methyl carbon, respectively. This suggests the presence of a heterocyclic ring with a carbon adjacent to a heteroatom and a quaternary carbon, which is consistent with the molecular formula CSUB19HSSUB1140. 
The relative integration of the signals can help to determine the number of each type of carbon. However, the question states that the relative integration is known but does not provide this information, so we cannot use it to determine the structure further. Therefore, the best choice is option C, which shows a heterocyclic ring with a quaternary carbon and a carbon adjacent to a heteroatom.

What Is the Structure of the Compound in the Following