What is/are the principal product(s)formed when excess methylmagnesium iodide reacts with p-hydroxyacetophenone ?

Question

Quizplus · Accepted Answer

The principal product formed when excess methylmagnesium iodide reacts with p-hydroxyacetophenone is III, which is the tertiary alcohol product. The excess methylmagnesium iodide will first form a Grignard reagent with p-hydroxyacetophenone, and then the Grignard reagent will attack the carbonyl group. The resulting intermediate will undergo protonation to give the tertiary alcohol product III as the principal product. None of the other compounds listed are expected to be the principal product under these reaction conditions.

What Is/are the Principal Product(s)formed When Excess Methylmagnesium Iodide Reacts