What is the correct structure for (S)-7-bromo-1-octyn-4-one?

Question

Quizplus · Accepted Answer

The correct structure for (S)-7-bromo-1-octyn-4-one is a terminal alkyne, which means that the bromine atom should be located at the first carbon of the triple bond, and the carbonyl group should be at the opposite end of the chain. Additionally, in order to assign the stereochemistry of the molecule, we need to look at the chirality center, which is at the second carbon of the triple bond. The priority of the substituents attached to this carbon (from highest to lowest) is: Br > C (triple bond) > H > CH3. The molecule is (S)-configured because the lowest priority substituent (CH3) is pointing away from the viewer. The correct structure should have the triple bond in the middle of the chain, the bromine at the first carbon, and the carbonyl at the last carbon. Therefore, only structure III matches these criteria.

What Is the Correct Structure for (S)-7-Bromo-1-Octyn-4-One