The ¹H NMR spectrum of a compound with formula C₇H₁₄O gives three signals.Which of these structures is a possible one for this compound?

Question

Quizplus · Accepted Answer

The fact that there are three signals in the spectrum indicates that there are three different types of carbon environments in the compound. Looking at the structures, Option D - 2,2-Dimethyl-3-pentanone - has three different types of carbons (a methyl carbon, two methylene carbons, and three methine carbons) which could give rise to three signals in the spectrum. The other options do not have enough different carbon environments to account for the three signals observed. Therefore, D is the best choice.

The 1H NMR Spectrum of a Compound with Formula C7H14O

The ¹H NMR Spectrum of a Compound with Formula C₇H₁₄O