If the methyl glycoside of an aldohexose is treated with HIO4,one molar equivalent of HCHO is formed but no HCOOH.What size ring is present in the glycoside?

Question

Quizplus · Accepted Answer

The formation of one molar equivalent of HCHO and no HCOOH upon treatment with HIO4 indicates that the glycoside has a five-membered ring. This is because a five-membered ring (furanose form) would have one primary alcohol group that can be oxidized to formaldehyde (HCHO), while a six-membered ring (pyranose form) would typically result in the formation of both HCHO and HCOOH.

If the Methyl Glycoside of an Aldohexose Is Treated with HIO4,one