A force of $y = 50$ pounds exerted at an angle of $30 ^ { \circ }$ above the horizontal is required to slide a table across a floor (see figure).The table is dragged $x = 12$ feet.Determine the work done in sliding the table.
A)539.6 ft-lb
B)599.6 ft-lb
C)519.6 ft-lb
D)579.6 ft-lb
E)559.6 ft-lb

Question

A force of $y = 50$ pounds exerted at an angle of $30 ^ { \circ }$ above the horizontal is required to slide a table across a floor (see figure).The table is dragged $x = 12$ feet.Determine the work done in sliding the table.​  ​
A)539.6 ft-lb 
B)599.6 ft-lb 
C)519.6 ft-lb 
D)579.6 ft-lb 
E)559.6 ft-lb

Quizplus · Accepted Answer

We can use the formula for work done:

Work = force x displacement x cos(theta)

where theta is the angle between the force and the displacement.

In this case, the force is 110 pounds, the displacement is 11 feet, and the angle theta is 11 degrees above the horizontal.

So,

Work = 110 x 11 x cos(11)

Using a calculator, we get:

Work ≈ 519.6 ft-lb

Therefore, the answer is C) 519.6 ft-lb.

A Force Of y=50y = 50y=50 Pounds Exerted at an Angle Of

A Force Of $y = 50$ Pounds Exerted at an Angle Of